document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=401805>Question 401805</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A Cessna 175 can average 130 mph. If a trip takes 2 hours one way and the return takes 1 hour and 15 minutes, find the wind speed, assuming it is constant.\r<BR>\n" );
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document.write( "This is an algebra equation.  I don't even know where to begin.  But I know that the wind speed would be x.  I'm not quite sure if I need to add or subtract the two time differences.  Thank you so much for helping me.  \r<BR>\n" );
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document.write( "Melissa </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #284338 by </B><A HREF=/tutors/aboutme.mpl?userid=rfer><B>rfer(16322)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rfer><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=284338\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> with the wind is x+y<BR>\n" );
document.write( "against the wind is x-y<BR>\n" );
document.write( "same distance both ways.<BR>\n" );
document.write( "2(x+y)=1.25(x-y)<BR>\n" );
document.write( "2x+2y=1.25x-1.25y<BR>\n" );
document.write( ".75x=3.25y<BR>\n" );
document.write( "x=4.33y<BR>\n" );
document.write( "--------<BR>\n" );
document.write( "2(x+y)=130<BR>\n" );
document.write( "replace x with 4.33y<BR>\n" );
document.write( "2(4.33y+y)=130<BR>\n" );
document.write( "9.66y=130<BR>\n" );
document.write( "y=14 mph wind </SPAN>\n" );
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