document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=401667>Question 401667</A>: <I><SPAN STYLE=\"word-break: break-all;\">  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #284330 by </B><A HREF=/tutors/aboutme.mpl?userid=charlth><B>charlth(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=charlth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=284330\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Solve each system by substitution. Determine whether the<BR>\n" );
document.write( "equations are independent, dependent, or inconsistent.\r<BR>\n" );
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document.write( "X=y+3<BR>\n" );
document.write( "3x-2y=4\r<BR>\n" );
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document.write( "Here is what I came up with using the substitution method:\r<BR>\n" );
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document.write( "X = y + 3<BR>\n" );
document.write( "3x - 2y = 4\r<BR>\n" );
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document.write( "Substituting the expression y + 3 for y from the 2nd equation into the 1st equation is as follows:\r<BR>\n" );
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document.write( "3x - 2(x + 3) = 4<BR>\n" );
document.write( "3x - 2x - 6 = 4<BR>\n" );
document.write( "3x - 2x - 6 = 4  (add/subtract like terms)<BR>\n" );
document.write( "x - 6 + 6 = 4  + 6 (add 6 to both sides)<BR>\n" );
document.write( "x = 10\r<BR>\n" );
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document.write( "Plugging in  If x = 10, then\r<BR>\n" );
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document.write( "10 = y + 3\r<BR>\n" );
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document.write( "10 - 3 = y + 3 - 3 (subtract -3 from both sides\r<BR>\n" );
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document.write( "6 = y\r<BR>\n" );
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document.write( "I found that the equations are independent of each other, because both sides does not equal.  Please correct me, if I'm wrong. </SPAN>\n" );
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