document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=43415>Question 43415</A>: <I><SPAN STYLE=\"word-break: break-all;\"> write in polar form: negative sqroot of 5+i </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #28430 by </B><A HREF=/tutors/aboutme.mpl?userid=venugopalramana><B>venugopalramana(3286)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=venugopalramana><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.geocities.com/venugopalramana/FREE_MATHS_ASSISTANCE.html valign=middle><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=28430\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> write in polar form: negative sqroot of 5+i<BR>\n" );
document.write( "Z=5+I<BR>\n" );
document.write( "|Z|=R=SQRT(5^2+1^2)=SQRT(26)<BR>\n" );
document.write( "TAN(THETA)=1/5.....THETA=TAN^-1 (1/5)=A SAY<BR>\n" );
document.write( "Z=R*E^(iA)={(26)^0.5}*{E^(iA)}<BR>\n" );
document.write( "-SQRT(Z)=-{(26)^0.25}*E^(iA/2)=-2.258*E^(0.1974i)....ANGLE IN RADIANS ..OR...<BR>\n" );
document.write( "=-2.258*E^(11.316i)....ANGLE IN DEGREES </SPAN>\n" );
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