document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=401669>Question 401669</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The area of a right-angled triangle is 48cm(squared). The base of the triangle is 4cm more than the height. Find the base and height of the triangle. I get confused with this question I know the answers from answer book and trial and error. I try to form into an quadratic equation like : h(h+4)=48cm(squared) but get confused plz help.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #284297 by </B><A HREF=/tutors/aboutme.mpl?userid=Earlsdon><B>Earlsdon(6294)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Earlsdon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=284297\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Start with the formula for the area of a triangle:<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=A+=+%281%2F2%29b%2Ah ALIGN=MIDDLE  ALT=\"A+=+%281%2F2%29b%2Ah\"   DISABLED_style= \"max-width:90%; height:auto;\" > and the area is given a 48 sq.cm., so...<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281%2F2%29b%2Ah+=+48 ALIGN=MIDDLE  ALT=\"%281%2F2%29b%2Ah+=+48\"   DISABLED_style= \"max-width:90%; height:auto;\" > but b = h+4, so substitute for b...<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%281%2F2%29%28h%2B4%29%2Ah+=+48 ALIGN=MIDDLE  ALT=\"%281%2F2%29%28h%2B4%29%2Ah+=+48\"   DISABLED_style= \"max-width:90%; height:auto;\" > Multiply both sides by 2.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28h%2B4%29%2Ah+=+96 ALIGN=MIDDLE  ALT=\"%28h%2B4%29%2Ah+=+96\"   DISABLED_style= \"max-width:90%; height:auto;\" > which becomes...<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=h%5E2%2B4h-96+=+0 ALIGN=MIDDLE  ALT=\"h%5E2%2B4h-96+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" > So there's the quadratic in h.  Solve by factoring.<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28h-8%29%28h%2B12%29+=+0 ALIGN=MIDDLE  ALT=\"%28h-8%29%28h%2B12%29+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=h+=+8 ALIGN=MIDDLE  ALT=\"h+=+8\"   DISABLED_style= \"max-width:90%; height:auto;\" > or <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=h+=+-12 ALIGN=MIDDLE  ALT=\"h+=+-12\"   DISABLED_style= \"max-width:90%; height:auto;\" > Discard the negative solution.<BR>\n" );
document.write( "The height is 8cm. and the base is h+4 = 12cm. </SPAN>\n" );
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