document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=43415>Question 43415</A>: <I><SPAN STYLE=\"word-break: break-all;\"> write in polar form: negative sqroot of 5+i </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #28429 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=28429\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> r = sqrt(x^2 + y^2)<BR>\n" );
document.write( "theta = arctan(y/x) ...I use q for theta<BR>\n" );
document.write( "so that<BR>\n" );
document.write( "r = sqrt(5 + 1) = sqrt(6)<BR>\n" );
document.write( "q = arctan(1/-sqrt(5))<BR>\n" );
document.write( "and thus in polar form we have<BR>\n" );
document.write( "(sqrt(6), arctan(1/-sqrt(5)) or about<BR>\n" );
document.write( "(2.449, -24.1°) </SPAN>\n" );
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