document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=401654>Question 401654</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Angles of a triangle:<BR>\n" );
document.write( "The second angle of a triangular garden is four times as large as the first.  The third angle is 45 degrees less than the sum or the other two angles.  Find the measure of each angle. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #284272 by </B><A HREF=/tutors/aboutme.mpl?userid=Alan3354><B>Alan3354(69443)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alan3354><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alan3354><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=284272\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The second angle of a triangular garden is four times as large as the first. The third angle is 45 degrees less than the sum or the other two angles. Find the measure of each angle.<BR>\n" );
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document.write( "A = 1st angle, B = 2nd, C = 3rd<BR>\n" );
document.write( "B = 4A<BR>\n" );
document.write( "C = A + B -45 = A + 4A + 45 = 5A + 45<BR>\n" );
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document.write( "A + 4A + 5A+45 = 180<BR>\n" );
document.write( "10A = 135º<BR>\n" );
document.write( "Can you finish it?<BR>\n" );
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