document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=43355>Question 43355</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solving rational expressions and equations\r<BR>\n" );
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document.write( "7 over 8 + 2 over 5 = x over 20\r<BR>\n" );
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document.write( "show work </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #28427 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=28427\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The first step in solving almost all fractional equations is to multiply all the terms by the lowest common denominator...here that is 40...so we get<BR>\n" );
document.write( "7/8 + 2/5 = x/20<BR>\n" );
document.write( "40(7/8 + 2/5 = x/20)<BR>\n" );
document.write( "35 + 16 = 2x<BR>\n" );
document.write( "2x = 51<BR>\n" );
document.write( "x = 51/2 </SPAN>\n" );
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