document.write( "Question 401464: I need help solving for the variable of \"x\" in this equation: \r
\n" ); document.write( "\n" ); document.write( "2^(x+1)= 192+ 2^(x-1)
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Algebra.Com's Answer #284134 by lwsshak3(11628)\"\" \"About 
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I need help solving for the variable of \"x\" in this equation:
\n" ); document.write( "2^(x+1)= 192+ 2^(x-1)
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\n" ); document.write( "\n" ); document.write( "2^(x+1)-2^(x-1)=192
\n" ); document.write( "factor out 2^(x+1)
\n" ); document.write( "2^(x+1)(1-(2^-2))=192 note:(2^(x+1)*2^-2=2^(x-1))
\n" ); document.write( "2^(x+1)(1-1/4)=192
\n" ); document.write( "2^(x+1)(3/4)=192
\n" ); document.write( "2^(x+1)=256
\n" ); document.write( "(x+1)log2=log256
\n" ); document.write( "x+1=log256/log2=8
\n" ); document.write( "ans: x=7\r
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