document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=401362>Question 401362</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A RECTANGLE IS 16M BY9M.FIND A SIDE OF THE SQUARE WHOSE AREA EQUALS THE AREA OF THE RECTANGLE. BY HOW MUCH DOES THE PERIMETER OF THE RECTANGLE EXCEED THE PERIMETER OF THE SQUARE. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #284050 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=284050\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A RECTANGLE IS 16M BY9M.FIND A SIDE OF THE SQUARE WHOSE AREA EQUALS THE AREA OF THE RECTANGLE. BY HOW MUCH DOES THE PERIMETER OF THE RECTANGLE EXCEED THE PERIMETER OF THE SQUARE.<BR>\n" );
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document.write( "Area of rectangle = 16*9= 144 m^2<BR>\n" );
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document.write( "Area of square = L^2 = 144<BR>\n" );
document.write( "L= 12 m<BR>\n" );
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document.write( "Perimeter of rectangle = 2*(L+W) ===>2*(16+9)<BR>\n" );
document.write( "Perimeter = 50 m<BR>\n" );
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document.write( "Perimeter of square = 4*L = 48 m<BR>\n" );
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document.write( "Difference = 2 m <BR>\n" );
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document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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