document.write( "Question 401302: A blimp flies at 60 miles per hour. A round trip of 40 miles into the wind and 40 miles with the wind takes 1.5 hours. What is the speed of the wind? \n" ); document.write( "
Algebra.Com's Answer #284049 by mananth(16949) You can put this solution on YOUR website! A blimp flies at 60 miles per hour. A round trip of 40 miles into the wind and 40 miles with the wind takes 1.5 hours. What is the speed of the wind?\r \n" ); document.write( "\n" ); document.write( ".. \n" ); document.write( "60 miles per hour. \n" ); document.write( "wind speed = w \n" ); document.write( "... \n" ); document.write( "against wind speed = 60-w \n" ); document.write( "with wind speed = 60+w \n" ); document.write( ".. \n" ); document.write( "40 miles into the wind \n" ); document.write( "40 miles with the wind takes 1.5 hours. \n" ); document.write( "... \n" ); document.write( "time with wind + time agianst wind = 1.5 hours \n" ); document.write( ".. \n" ); document.write( "t=d/r \n" ); document.write( " \n" ); document.write( "LCD = (60+w)(60-w)\r \n" ); document.write( "\n" ); document.write( ".. \n" ); document.write( "multiply by the LCD \n" ); document.write( "40(60-w)+40(60+w)=1.5(60+w)(60-w)\r \n" ); document.write( "\n" ); document.write( "2400-40w+2400+40w=1.5(3600-w^2) \n" ); document.write( "4800=1.5(3600-w^2) \n" ); document.write( "divide by 1.5 \n" ); document.write( "3200=3600-w^2 \n" ); document.write( "w^2=3600-3200 \n" ); document.write( "w^2=400 \n" ); document.write( "w=20 mph ===>speed of wind \n" ); document.write( "... \n" ); document.write( "m.ananth@hotmail.ca \n" ); document.write( " |