document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=401080>Question 401080</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the vertices of the hyperbola defined by this equation: (y+8)^2/36 - (x -7)^2/1=1.It tells me to put it in this form (x1,y1),(x2,y2).I have no idea How to do this,please help.I'd appreciate it :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #284035 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=284035\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Find the vertices of the hyperbola defined by this equation: (y+8)^2/36 - (x -7)^2/1=1.It tells me to put it in this form (x1,y1),(x2,y2).I have no idea How to do this,please help.I'd appreciate it <BR>\n" );
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document.write( "(y+8)^2/36 - (x -7)^2/1=1<BR>\n" );
document.write( "This is a hyperbola with center at (7,-8) and the transverse axis is vertical. <BR>\n" );
document.write( "Standard form of the hyperbola: (x-h)^2/a^2-(y-k)^2/b^2=1 (transverse axis horizontal) or (y-k)^2/a^2-(x-h)^2/b^2=1 (transverse axis vertical,like this case)<BR>\n" );
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document.write( "a^2=36<BR>\n" );
document.write( "a=6<BR>\n" );
document.write( "b^2=1<BR>\n" );
document.write( "b=1<BR>\n" );
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document.write( "The vertex lies somewhere on the vertical transverse axis,so its x-coordinate is already determined to be 7. On this axis the vertices are 6 or \"a\" units above and below the center y-coordinate,-8.Therefore, the vertices are at (7,-2) and (7,-14)<BR>\n" );
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document.write( "ans:(x,y) coordinates of the vertices are (7,-2) and (7,-14)\r<BR>\n" );
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document.write( "see the graph below to see what the hyperbola looks like:<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+300%2C+200%2C+-6%2C+20%2C+-20%2C+10%2C+-8%2B%2836%2B36%2A%28x-7%29%5E2%29%5E.5%2C-8-%2836%2B36%2A%28x-7%29%5E2%29%5E.5%29+ ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
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