document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=401357>Question 401357</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of 3 integers is 251.  The sum of the 1st and 2nd integers exceeds the 3rd by 45.  The 3rd integer is 42 less than the 1st.  Find the 3 integers </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #284031 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=284031\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> We have the system\r<BR>\n" );
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document.write( "a + b + c = 251<BR>\n" );
document.write( "a + b = c + 45<BR>\n" );
document.write( "c = a + 42\r<BR>\n" );
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document.write( "Substituting the second equation into the first, we obtain\r<BR>\n" );
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document.write( "(c + 45) + c = 251 --> 2c + 45 = 251 --> c = 103. Replacing c into the third equation we get a = 61, and it follows that b = 87. </SPAN>\n" );
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