document.write( "Question 401355: I need to solve by using the elimination method but the fraction is throwing me off and I am not sure how to solve this one. Thank you \r
\n" ); document.write( "\n" ); document.write( "0.3x-0.2y=4\r
\n" ); document.write( "\n" ); document.write( "0.2x-0.3y=5/23
\n" ); document.write( "

Algebra.Com's Answer #284028 by dnanos(83)\"\" \"About 
You can put this solution on YOUR website!
First multiply by 10 both equations
\n" ); document.write( "3x+2y=40
\n" ); document.write( "2x-3y=50/23
\n" ); document.write( "then multiply the first one by 2 and the second by -3
\n" ); document.write( "6x+4y=80
\n" ); document.write( "-6x+9y=-150/23\r
\n" ); document.write( "\n" ); document.write( "Then add and keep the first one for next steps
\n" ); document.write( "3x+2y=40
\n" ); document.write( "13y=80-150/23
\n" ); document.write( "so
\n" ); document.write( "3x+2y=40
\n" ); document.write( "13y=(1840-150)/23
\n" ); document.write( "so
\n" ); document.write( "3x+2y=40
\n" ); document.write( "13y=1690/23
\n" ); document.write( "We divide the second equation by 13 (because 169=13*13)
\n" ); document.write( "3x+2y=40
\n" ); document.write( "13y/13=1690/13*23
\n" ); document.write( "so
\n" ); document.write( "3x+2y=40
\n" ); document.write( "y=130/23
\n" ); document.write( "then we replace the y value in the first equation.
\n" ); document.write( "3x+2*130/23=40
\n" ); document.write( "y=130/23
\n" ); document.write( "so
\n" ); document.write( "3x=40-260/23
\n" ); document.write( "y=130/23
\n" ); document.write( "so
\n" ); document.write( "3x=(920-260)/23
\n" ); document.write( "y=130/23
\n" ); document.write( "so
\n" ); document.write( "3x=660/23
\n" ); document.write( "y=130/23
\n" ); document.write( "We divide the first equation by 3
\n" ); document.write( "x=220/23
\n" ); document.write( "y=130/23\r
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