document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=401141>Question 401141</A>: <I><SPAN STYLE=\"word-break: break-all;\"> During the first part of a trip a canoeist travels 48 miles at a certain speed. The canoeist travels 19 miles on the second part of the trip at a speed 5 mph slower. The total time for the trip is 3 hours. What was the speed on each part of the trip? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #283995 by </B><A HREF=/tutors/aboutme.mpl?userid=robertb><B>robertb(5830)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=robertb><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=robertb><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=283995\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let r = speed at the 1st part of trip ==> time for 1st part = 48/r<BR>\n" );
document.write( "==> r - 5 = speed at 2nd part of trip ==> time for 2nd part = 19/(r-5).<BR>\n" );
document.write( "both from the formula t = d/r = distance/rate.\r<BR>\n" );
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document.write( "Then <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=48%2Fr+%2B+19%2F%28r-5%29+=+3 ALIGN=MIDDLE  ALT=\"48%2Fr+%2B+19%2F%28r-5%29+=+3\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<==> 48(r-5) + 19r = 3r(r-5)<BR>\n" );
document.write( "<==> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=48r+-+240+%2B+19r+=+3r%5E2+-+15r ALIGN=MIDDLE  ALT=\"48r+-+240+%2B+19r+=+3r%5E2+-+15r\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<==> <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=3r%5E2+-+82r+%2B+240+=+0 ALIGN=MIDDLE  ALT=\"3r%5E2+-+82r+%2B+240+=+0\"   DISABLED_style= \"max-width:90%; height:auto;\" > <==> (r - 24)(3r - 10) = 0<BR>\n" );
document.write( "==> r = 24, 10/3<BR>\n" );
document.write( "Eliminate r = 10/3, because it would make r - 5 negative.<BR>\n" );
document.write( "Hence the speed in the 1st part is 24 mph, and the speed in the 2nd part is 19 mph. </SPAN>\n" );
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