document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=401310>Question 401310</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Im having trouble with some word problems i have many for my homework i understand the easy work ones but i thought i put 3 differnt kinds up so that i can finish the rest of my homework by examples of these ones.Can you please help me?\r<BR>\n" );
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document.write( "1)A jogger ran 8 miles and then walked 6miles. The jogger's  running speed was 5 miles per hour faster then her walking speed. Th total time for jogging and walking was 2 hrs find the joggers walking speed and jogging speed.<BR>\n" );
document.write( " i made a table<BR>\n" );
document.write( "        D       R       T\r<BR>\n" );
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document.write( "run   8mi      x+5\r<BR>\n" );
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document.write( "walk  6mi       x\r<BR>\n" );
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document.write( "total                   2hrs\r<BR>\n" );
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document.write( "i came up the equation   8      6  <BR>\n" );
document.write( "                        ___ + ____   =2<BR>\n" );
document.write( "                       x+5     x\r<BR>\n" );
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document.write( "2)Another one i cant figure out is A car travels for 100miles at a uniform speed. If the speed is increased by 5 miles per hour, the trip would take one hour less time. What is the car's original speed?\r<BR>\n" );
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document.write( "Im not sure how to get this one except i know to divide distance by time and the distance is 100 and the time is x-1 and the rate is x+5 i think i dont know how to set this up.\r<BR>\n" );
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document.write( "3) Working together amy and bob can complete a job in 12 hours. Working alone it takes amy 4/3 as much time as bob to do the job how long will it take each to do the job working alone?\r<BR>\n" );
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document.write( "For this i have a table and some work done but i think its the 4/3 is throwing me off\r<BR>\n" );
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document.write( "            time hrs             job\r<BR>\n" );
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document.write( "amy        4/3x                1 divided by 4/3x<BR>\n" );
document.write( " bob        x                    i divided by x<BR>\n" );
document.write( "total                             1 divided by 12\r<BR>\n" );
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document.write( "i divided both sides by 12x(4/3x)<BR>\n" );
document.write( "and got 12x+12(4/3x) = x(4/3x)\r<BR>\n" );
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document.write( "12x+16x=4/3x^2<BR>\n" );
document.write( "28x=4/3x^2<BR>\n" );
document.write( "4/3x^2-28x=0\r<BR>\n" );
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document.write( "now im stuck\r<BR>\n" );
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document.write( "IF someone could please help me that would be wonderfull and i thank you soo much\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #283992 by </B><A HREF=/tutors/aboutme.mpl?userid=lwsshak3><B>lwsshak3(11628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=lwsshak3><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=283992\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1)A jogger ran 8 miles and then walked 6miles. The jogger's running speed was 5 miles per hour faster then her walking speed. Th total time for jogging and walking was 2 hrs find the joggers walking speed and jogging speed.\r<BR>\n" );
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document.write( "let x=walking speed<BR>\n" );
document.write( "then x+5=running speed<BR>\n" );
document.write( "travel time = distance/speed\r<BR>\n" );
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document.write( "(6/x)+(8/(x+5))=2<BR>\n" );
document.write( "LCD=x(x+5)<BR>\n" );
document.write( "6(x+5)+8x=2x(x+5)<BR>\n" );
document.write( "6x+30+8x=2x^2+10x<BR>\n" );
document.write( "2x^2-4x-30=0<BR>\n" );
document.write( "x^2-2x-15=0<BR>\n" );
document.write( "(x-5)(x+3)=0<BR>\n" );
document.write( "x-5=0<BR>\n" );
document.write( "x=5<BR>\n" );
document.write( "x+3=0<BR>\n" );
document.write( "x=-3 (reject)<BR>\n" );
document.write( "ans:<BR>\n" );
document.write( "walking speed=5 miles per hour<BR>\n" );
document.write( "jogging speed = x+5 = 10 miles per hour \r<BR>\n" );
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document.write( "2)Another one i cant figure out is A car travels for 100miles at a uniform speed. If the speed is increased by 5 miles per hour, the trip would take one hour less time. What is the car's original speed?\r<BR>\n" );
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document.write( "let x=car's original speed<BR>\n" );
document.write( "then x+5= car's faster speed<BR>\n" );
document.write( "travel time = distance/speed\r<BR>\n" );
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document.write( "100/x-100/(x+5)=1<BR>\n" );
document.write( "100(x+5)-100x=x(x+5)<BR>\n" );
document.write( "100x+500-100x=x^2+5x<BR>\n" );
document.write( "x^2+5x-500=0<BR>\n" );
document.write( "(x+25)(x-20)=0<BR>\n" );
document.write( "x+25=0<BR>\n" );
document.write( "x=-25 (reject)<BR>\n" );
document.write( "x-20=0<BR>\n" );
document.write( "x=20<BR>\n" );
document.write( "ans: The car's original speed=20 miles per hour\r<BR>\n" );
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document.write( "3) Working together amy and bob can complete a job in 12 hours. Working alone it takes amy 4/3 as much time as bob to do the job how long will it take each to do the job working alone?\r<BR>\n" );
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document.write( "let x=hours Bob can do the job alone<BR>\n" );
document.write( "his hourly rate would then be 1/x<BR>\n" );
document.write( "let(4/3)x=4x/3 hours Amy can do the job alone<BR>\n" );
document.write( "her hourly rate would then be 3/4x (1/(4x/3)=3/4x)<BR>\n" );
document.write( "working together they can complete the job in 12 hours<BR>\n" );
document.write( "so, their hourly rate working together=1/12<BR>\n" );
document.write( "sum of hourly rates of individuals = hourly rate working together\r<BR>\n" );
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document.write( "(1/x)+(3/4x)=1/12<BR>\n" );
document.write( "LCD=4x<BR>\n" );
document.write( "4+3=x/3<BR>\n" );
document.write( "7=x/3<BR>\n" );
document.write( "x=21<BR>\n" );
document.write( "ans: <BR>\n" );
document.write( "Bob can do the job alone in 21 hours<BR>\n" );
document.write( "Amy can do the job alone in 4/3*21=28 hours\r<BR>\n" );
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document.write( " </SPAN>\n" );
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