document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=401310>Question 401310</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Im having trouble with some word problems i have many for my homework i understand the easy work ones but i thought i put 3 differnt kinds up so that i can finish the rest of my homework by examples of these ones.Can you please help me?\r<BR>\n" );
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document.write( "1)A jogger ran 8 miles and then walked 6miles. The jogger's  running speed was 5 miles per hour faster then her walking speed. Th total time for jogging and walking was 2 hrs find the joggers walking speed and jogging speed.<BR>\n" );
document.write( " i made a table<BR>\n" );
document.write( "        D       R       T\r<BR>\n" );
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document.write( "run   8mi      x+5\r<BR>\n" );
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document.write( "walk  6mi       x\r<BR>\n" );
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document.write( "total                   2hrs\r<BR>\n" );
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document.write( "i came up the equation   8      6  <BR>\n" );
document.write( "                        ___ + ____   =2<BR>\n" );
document.write( "                       x+5     x\r<BR>\n" );
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document.write( "2)Another one i cant figure out is A car travels for 100miles at a uniform speed. If the speed is increased by 5 miles per hour, the trip would take one hour less time. What is the car's original speed?\r<BR>\n" );
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document.write( "Im not sure how to get this one except i know to divide distance by time and the distance is 100 and the time is x-1 and the rate is x+5 i think i dont know how to set this up.\r<BR>\n" );
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document.write( "3) Working together amy and bob can complete a job in 12 hours. Working alone it takes amy 4/3 as much time as bob to do the job how long will it take each to do the job working alone?\r<BR>\n" );
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document.write( "For this i have a table and some work done but i think its the 4/3 is throwing me off\r<BR>\n" );
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document.write( "            time hrs             job\r<BR>\n" );
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document.write( "amy        4/3x                1 divided by 4/3x<BR>\n" );
document.write( " bob        x                    i divided by x<BR>\n" );
document.write( "total                             1 divided by 12\r<BR>\n" );
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document.write( "i divided both sides by 12x(4/3x)<BR>\n" );
document.write( "and got 12x+12(4/3x) = x(4/3x)\r<BR>\n" );
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document.write( "12x+16x=4/3x^2<BR>\n" );
document.write( "28x=4/3x^2<BR>\n" );
document.write( "4/3x^2-28x=0\r<BR>\n" );
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document.write( "now im stuck\r<BR>\n" );
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document.write( "IF someone could please help me that would be wonderfull and i thank you soo much\r<BR>\n" );
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document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #283982 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=283982\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 1)A jogger ran 8 miles and then walked 6miles. The jogger's running speed was 5 miles per hour faster then her walking speed. Th total time for jogging and walking was 2 hrs find the joggers walking speed and jogging speed.<BR>\n" );
document.write( "i made a table<BR>\n" );
document.write( "D R T <BR>\n" );
document.write( "run 8mi x+5 <BR>\n" );
document.write( "walk 6mi x <BR>\n" );
document.write( "total 2hrs <BR>\n" );
document.write( "i came up the equation <BR>\n" );
document.write( "8/(x+5) + 6/x = 2 <BR>\n" );
document.write( "Multiply thru by x(x+5) to get:<BR>\n" );
document.write( "8x + 6(x+5) = 2x(x+5)<BR>\n" );
document.write( "14x+30 = 2x^2+10x<BR>\n" );
document.write( "---<BR>\n" );
document.write( "2x^2-4x-30 = 0<BR>\n" );
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document.write( "x^2-2x-15 = 0<BR>\n" );
document.write( "(x-5)(x+3) = 0<BR>\n" );
document.write( "Positive solution:<BR>\n" );
document.write( "x = 5 mph (walking rate)<BR>\n" );
document.write( "---<BR>\n" );
document.write( "x+5 = 10 mph (jogging rate)<BR>\n" );
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document.write( "2)Another one i cant figure out is A car travels for 100miles at a uniform speed. If the speed is increased by 5 miles per hour, the trip would take one hour less time. What is the car's original speed? <BR>\n" );
document.write( "Im not sure how to get this one except i know to divide distance by time and the distance is 100 and the time is x-1 and the rate is x+5 i think i dont know how to set this up.<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Original DATA:<BR>\n" );
document.write( "dist = 100 ; rate = x mph ; time = d/r = 100/x hrs<BR>\n" );
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document.write( "New DATA:<BR>\n" );
document.write( "dist = 100 ; rate = x+5 mph ; time = 100/(x+5) hrs<BR>\n" );
document.write( "---<BR>\n" );
document.write( "Equations:<BR>\n" );
document.write( "old time - new time = 1 hr<BR>\n" );
document.write( "100/x - 100/(x+5) = 1<BR>\n" );
document.write( "Multiply thru by x(x+5) to get:<BR>\n" );
document.write( "100x+500 - 100x = x(x+5)<BR>\n" );
document.write( "x^2+5x-500 = 0<BR>\n" );
document.write( "(x-20)(x+25) = 0<BR>\n" );
document.write( "Positive solution:<BR>\n" );
document.write( "x = 20 mph<BR>\n" );
document.write( "x+5 = 25 mph<BR>\n" );
document.write( "======================  \r<BR>\n" );
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document.write( "3) Working together amy and bob can complete a job in 12 hours. Working alone it takes amy 4/3 as much time as bob to do the job how long will it take each to do the job working alone? <BR>\n" );
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document.write( "Together time = 12 hr/job ; rate = 1/12 job/hr<BR>\n" );
document.write( "Let Bob time = x hr/job ; Bob's rate = 1/x job/hr<BR>\n" );
document.write( "Amy's time = (4x/3) hr/job ; Amy's rate = 3/(4x) job/hr<BR>\n" );
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document.write( "Equation:<BR>\n" );
document.write( "rate + rate = together rate<BR>\n" );
document.write( "1/x + 3/(4x) = 1/12<BR>\n" );
document.write( "Multiply thru by 12x to get:<BR>\n" );
document.write( "12 + 9 = x<BR>\n" );
document.write( "x = 13 hrs (Bob's time)<BR>\n" );
document.write( "(4/3)x = (4/3)13 = 52/3 = 17 1/3 hrs (Amy's time)<BR>\n" );
document.write( "===================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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