document.write( "Question 401264: y=2x-4
\n" ); document.write( "y=-3x+1\r
\n" ); document.write( "\n" ); document.write( "I'm supposed to choose one and solve for either x or y but my teacher had no time to go over the steps very well in order to use substitution. I really need detailed help before monday!! Pleassseee Help!! \n" ); document.write( "
Algebra.Com's Answer #283953 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
y= 2x - 4
\n" ); document.write( "y=-3x + 1
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\n" ); document.write( "The first equation y = 2x - 4, therefore you can substitute y with 2x-4 for y in the 2nd equation
\n" ); document.write( "2x - 4 = -3x + 1
\n" ); document.write( "Add 3x to both sides
\n" ); document.write( "2x + 3x - 4 = 1
\n" ); document.write( "Add 4 to both sides
\n" ); document.write( "2x + 3x = 1 + 4
\n" ); document.write( "5x = 5
\n" ); document.write( "x = \"5%2F5\"
\n" ); document.write( "x = 1
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\n" ); document.write( "Use 1st equation to find y: replace x with 1
\n" ); document.write( "y = 2(1) - 4
\n" ); document.write( "y = 2 - 4
\n" ); document.write( "y = -2
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\n" ); document.write( "Check solutions by replacing x and y in the 2nd equation
\n" ); document.write( "-2 = -3(1) + 1
\n" ); document.write( "-2 = -3 + 1; confirms our solutions of x=1; y=-2
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