document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=401199>Question 401199</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of three integers is 52. The second integer is 3 more than the first. The third integer is 1 more than twice the first. What are the integers? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #283888 by </B><A HREF=/tutors/aboutme.mpl?userid=sofiyac><B>sofiyac(983)</B></A><img src=\"/images/stars/stars-11.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sofiyac><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sofiyac><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=283888\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the first integer be x<BR>\n" );
document.write( "then the second will be x+3<BR>\n" );
document.write( "then the third one will be 2x+1<BR>\n" );
document.write( "Now you can add them up and make sum equal to 52<BR>\n" );
document.write( "x+x+3+2x+1=52<BR>\n" );
document.write( "4x+4=52<BR>\n" );
document.write( "4x=48<BR>\n" );
document.write( "x=12<BR>\n" );
document.write( "so since we named the first one x, then the first one is 12<BR>\n" );
document.write( "then the second one is 12+3=15<BR>\n" );
document.write( "then the third one is 2*12+1=25<BR>\n" );
document.write( ":0) </SPAN>\n" );
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