document.write( "Question 401170: Find the foci for the hyperbola, using this equation (x+2)^2/81 - (y+4)^2/4 = 1.It tells me to put it in this form (x1,y1),(x2,y2).Please help I don't know how to solve this. \n" ); document.write( "

Algebra.Com's Answer #283883 by ewatrrr(24785) $\"\"$ $\"About$

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document.write( "Hi
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document.write( "Standard Form of an Equation of an Hyperbola is   where Pt(h,k) is a center,  
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document.write( "and the vertices are 'a' units right and left of center.
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document.write( "(x+2)^2/81 - (y+4)^2/4 = 1   | a = 9 for this hyperbola
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document.write( "Center is Pt(-2,-4), therefore the vertices would be (-11,-4)  and (7,-4)
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document.write( "Foci: c = sqrt(a^2 + b^2)}}}  = sqrt(85)= 9.22
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document.write( "Pt(-11.22, -4) and Pt(7.22, -4)\r
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