document.write( "Question 401140: I have spent hours on this problem and cannot solve it. There must be a step I am missing. Log3 65 a=3, x=65, b=10
\n" ); document.write( "Log3 65 = log 65/log 3 = approx. 3.7997 (the 3 on log is subscript)
\n" ); document.write( "How do you get that answer? I have a bunch to work .
\n" ); document.write( " \n" ); document.write( "
Algebra.Com's Answer #283870 by lwsshak3(11628)\"\" \"About 
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I have spent hours on this problem and cannot solve it. There must be a step I am missing. Log3 65 a=3, x=65, b=10
\n" ); document.write( "Log3 65 = log 65/log 3 = approx. 3.7997 (the 3 on log is subscript)
\n" ); document.write( "How do you get that answer? I have a bunch to work\r
\n" ); document.write( "\n" ); document.write( "To solve this problem you need to remember the exponential form of logarithms; that is, the base raised to the logarithm of the number is equal to the number.
\n" ); document.write( "In your problem, the base=3,and number=65 and you need to find the logarithm of the number. So, what you have in exponential form is this:\r
\n" ); document.write( "\n" ); document.write( "3^x=65
\n" ); document.write( "using logarithms to solve for x, the logarithm of 65 with base=3
\n" ); document.write( "xlog3=log65
\n" ); document.write( "x=log65/log3
\n" ); document.write( "x=3.79969104\r
\n" ); document.write( "\n" ); document.write( "When working with logarithms,if you have 2 of the factors mentioned above, you can always find the third. \n" ); document.write( "
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