document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=401182>Question 401182</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Gardening: a homeowner designs a rectangular garden such that the length is 20 feet more than twice the width. if 310 feet of picket fencing are to be used, find the length and width of the garden? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #283869 by </B><A HREF=/tutors/aboutme.mpl?userid=nerdybill><B>nerdybill(7384)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=nerdybill><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=nerdybill><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=283869\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Gardening: a homeowner designs a rectangular garden such that the length is 20 feet more than twice the width. if 310 feet of picket fencing are to be used, find the length and width of the garden?<BR>\n" );
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document.write( "Let w = width<BR>\n" );
document.write( "then<BR>\n" );
document.write( "2w+20 = length<BR>\n" );
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document.write( "\"perimeter of garden\" = \"amount of fencing\"<BR>\n" );
document.write( "2(w + 2w+20) = 310<BR>\n" );
document.write( "2(3w+20) = 310<BR>\n" );
document.write( "3w+20 = 155<BR>\n" );
document.write( "3w = 135<BR>\n" );
document.write( "w = 45 feet (width)<BR>\n" );
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document.write( "Length:<BR>\n" );
document.write( "2w+20 = 2(45)+20 = 90+20 = 110 feet\r<BR>\n" );
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