document.write( "Question 401187: Travel Distance: Two buses leave the same city at the same time moving in opposite directions. one travels at a rate of 5 miles per hour faster than the other. after 3 hours they are 375 miles apart. how far did each bus travel? \n" ); document.write( "

Algebra.Com's Answer #283861 by josmiceli(19441) $\"\"$ $\"About$

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Let $\"s\"$ = the speed of the slower bus
\n" ); document.write( "Let $\"d\"$ = the distance the slower bus travels
\n" ); document.write( " $\"s+%2B+5\"$ = the speed of the faster bus
\n" ); document.write( " $\"375+-+d\"$ = distance the faster bus travels
\n" ); document.write( " $\"3\"$ hrs = time for both buses
\n" ); document.write( "-------------------------------------
\n" ); document.write( "slower bus:
\n" ); document.write( "(1) $\"+d+=+s%2A3\"$
\n" ); document.write( "faster bus:
\n" ); document.write( "(2) $\"375+-+d+=+%28s+%2B+5%29%2A3\"$
\n" ); document.write( "From (1):
\n" ); document.write( "(1) $\"s+=+d%2F3\"$
\n" ); document.write( "Substitute (1) into (2):
\n" ); document.write( "(2) $\"375+-+d+=+%28d%2F3+%2B+5%29%2A3\"$
\n" ); document.write( "(2) $\"375+-+d+=+d+%2B+15\"$
\n" ); document.write( "(2) $\"2d+=+360\"$
\n" ); document.write( " $\"d+=+180\"$
\n" ); document.write( " $\"375+-+d+=+195\"$
\n" ); document.write( "The slower bus went 180 mi and the faster bus went 195 mi
\n" ); document.write( "check answer:
\n" ); document.write( "(1) $\"+180+=+s%2A3\"$
\n" ); document.write( "(1) $\"s+=+60\"$
\n" ); document.write( "(2) $\"375+-+180+=+%28s+%2B+5%29%2A3\"$
\n" ); document.write( "(2) $\"195+=+3s+%2B+15\"$
\n" ); document.write( "(2) $\"3s+=+180\"$
\n" ); document.write( "(2) $\"s+=+60\"$
\n" ); document.write( "OK \n" ); document.write( "

\n" );