document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=401165>Question 401165</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A rectangle has a length 7 meters longer than double the width. The perimeter is 134 meters. Find the dimensions of the rectangle.\r<BR>\n" );
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document.write( "Thank you soooooo very much!!!!! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #283851 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=283851\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> A rectangle has a length 7 meters longer than double the width. The perimeter is 134 meters. Find the dimensions of the rectangle. <BR>\n" );
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document.write( "Let the width be \"x\".<BR>\n" );
document.write( "Then the length is \"2x+7\".<BR>\n" );
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document.write( "Perimeter = 2(width + length)<BR>\n" );
document.write( "134 = 2(x + 2x+7)<BR>\n" );
document.write( "67 = 3x+7<BR>\n" );
document.write( "3x = 60<BR>\n" );
document.write( "x = 20 meters (width)<BR>\n" );
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document.write( "2x+7 = 47 meters (length)<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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