document.write( "Question 401146: I need help explaining the changes between y = |x| and y= |2x-1|. I need to comment on what the 2 and the 1 do to the original graph of y=|x|. \n" ); document.write( "

Algebra.Com's Answer #283843 by stanbon(75887) $\"\"$ $\"About$

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I need help explaining the changes between y = |x| and y= |2x-1|. I need to comment on what the 2 and the 1 do to the original graph of y=|x|.
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\n" ); document.write( "Regarding y = |x|, notice that y is zero when x=0.
\n" ); document.write( "---
\n" ); document.write( "Regarding y = |2x-1|, y will be zero when 2x-1=0
\n" ); document.write( ": that is when x = 1/2.
\n" ); document.write( "--
\n" ); document.write( "Starting with \"x\",
\n" ); document.write( "the 2 is applied 1st, so all the y-values are multiplied by 2:
\n" ); document.write( "that narrows the graph of y = |x|.
\n" ); document.write( "---
\n" ); document.write( "The -1 is then applied; that moves the graph to the right.
\n" ); document.write( "---
\n" ); document.write( "I'll graph the two functions on the same axes:
\n" ); document.write( " $\"graph%28400%2C300%2C-10%2C10%2C-10%2C10%2Cabs%28x%29%2Cabs%282x-1%29%29\"$
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H. \n" ); document.write( "

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