document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=401149>Question 401149</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3 (2x-6)+4(5x+3) = SQ Root of 36 +8(2x-1)\r<BR>\n" );
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document.write( "Why is the answer a positive .4?\r<BR>\n" );
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document.write( "I think it should be a negative.  -.4 divided by 10.  shouldn't that be a negative? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #283841 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=283841\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 3 (2x-6)+4(5x+3) = Sqrt(36)+ 8(2x-1) <BR>\n" );
document.write( "Why is the answer a positive .4? <BR>\n" );
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document.write( "6x-18 + 20x+12 = 6 + 16x-8<BR>\n" );
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document.write( "26x-6 = 16x-2<BR>\n" );
document.write( "10x = 4<BR>\n" );
document.write( "x = +0.4<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "----- </SPAN>\n" );
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