document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=400917>Question 400917</A>: <I><SPAN STYLE=\"word-break: break-all;\"> What is the solution to this system of equations? Why did you chose the method you did?\r<BR>\n" );
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document.write( "x+y=10<BR>\n" );
document.write( "x-y=22\r<BR>\n" );
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document.write( "I believe I use the substitution method, but I am not sure. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #283727 by </B><A HREF=/tutors/aboutme.mpl?userid=richard1234><B>richard1234(7193)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=richard1234><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=richard1234><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=283727\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Either method works, but in this case addition is easier. This is because if we add the two equations, the y's cancel out and we get 2x = 32 --> x = 16. Replacing x into either equation we get y = -6. </SPAN>\n" );
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