document.write( "Question 43338: I have to subtract as indicated and simplify the results if possible. Can someone show me how to do this?\r
\n" ); document.write( "\n" ); document.write( "6y/y^2-4 - 3/y+2\r
\n" ); document.write( "\n" ); document.write( "The 6y is over the y^2-4 and the 3 is over the y+2
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Algebra.Com's Answer #28372 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
(6y)/(y^2-4) - (3)/(y+2)\r
\n" ); document.write( "\n" ); document.write( "The least common denominator (LCD) is (y+2)(y-2)=y^2-4\r
\n" ); document.write( "\n" ); document.write( "Convert each fraction so each has the LCD as its denominator, as follows:\r
\n" ); document.write( "\n" ); document.write( "(6y)/(y^2-4) - [3(y-2)]/(y^2-4)\r
\n" ); document.write( "\n" ); document.write( "Subtract as indicated:\r
\n" ); document.write( "\n" ); document.write( "[6y-3(y-2)]/(y^2-4)
\n" ); document.write( "[3y+6]/(y^2-4)
\n" ); document.write( "Factor to get:\r
\n" ); document.write( "\n" ); document.write( "[3(y+2)]/[(y+2)(y-2)]\r
\n" ); document.write( "\n" ); document.write( "=3/(y-2)\r
\n" ); document.write( "\n" ); document.write( "Cheers,
\n" ); document.write( "stan H.\r
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