document.write( "Question 400837: Two cyclists, 60 miles apart, start riding toward each other at the same time. One cycles 2 times as fast as the other. If they meet 2 hours later, what is the speed (in mi/h) of the faster cyclist? \n" ); document.write( "
Algebra.Com's Answer #283712 by josmiceli(19441)\"\" \"About 
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you can think of 1 standing still and the
\n" ); document.write( "other moving at the sum of their speeds
\n" ); document.write( "\"60+=+%28r%2B+2r%29%2A2\"
\n" ); document.write( "\"60+=+6r\"
\n" ); document.write( "\"r++10\" mi/hr
\n" ); document.write( "\"2r+=+20\" mi/hr
\n" ); document.write( "The speed of the faster cyclist was 20 mi/hr
\n" ); document.write( "check answer:
\n" ); document.write( "slower cyclist:
\n" ); document.write( "\"d%5B1%5D+=+10%2A2\"
\n" ); document.write( "\"d%5B1%5D+=+20\" mi
\n" ); document.write( "faster cyclist:
\n" ); document.write( "\"d%5B2%5D+=+20%2A2\"
\n" ); document.write( "\"d%5B2%5D+=+40\" mi
\n" ); document.write( "\"20+%2B+40+=+60\"
\n" ); document.write( "OK
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