document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=43345>Question 43345</A>This question is from textbook <A HREF=http://www.amazon.com/exec/obidos/ASIN/0534494498/algebrahomeworkh></A><BR>\n" );
document.write( ": <I><SPAN STYLE=\"word-break: break-all;\"> hello, I need to rationalize the denominator to the following: square root of 3x divided by square root of x minus square root of 3.  Thank you for your time!<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #28371 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=28371\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> rationalize the denominator to the following: square root of 3x divided by square root of x minus square root of 3. \r<BR>\n" );
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document.write( "Multiply numerator and denominator by (sqrtx + sqrt3) to get:\r<BR>\n" );
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document.write( "[(sqrt(3x)(sqrtx + sqrt3)]/[(sqrtx-sqrt3)(sqrtx+sqrt3)]\r<BR>\n" );
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document.write( "=[xsqrt3 + 3sqrtx]/(x-3)\r<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
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