document.write( "Question 400662: x^6-9x^3-10=0 \n" ); document.write( "
Algebra.Com's Answer #283603 by richard1234(7193)\"\" \"About 
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Let \"z+=+x%5E3\" so that we can obtain a quadratic:\r
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\n" ); document.write( "\n" ); document.write( "\"z%5E2+-+9z+-+10+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "\"%28z-10%29%28z%2B1%29+=+0\"\r
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\n" ); document.write( "\n" ); document.write( "z = 10, z = -1. Since \"z+=+x%5E3\" we have\r
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\n" ); document.write( "\n" ); document.write( "\"x%5E3+=+10\", \"x%5E3+=+-1\" Each of these equations has three complex roots that form roots of unity. For the first equation, we have \"x+=+root%283%2C+10%29\" as well as \"x+=+5+%2B-+5sqrt%283%29i\". The second equation has roots \"x+=+-1\" as well as \"x+=+1%2F2+%2B-+%28sqrt%283%29%2F2%29i\".
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