document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=400609>Question 400609</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Tal is making a nut mixture to sell at the local farmers' market. He mixes 5 pounds of pistachios with a nut mixture that is 70% pistachios.  The resulting mixture is 80% pistachios.  How many pounds of nut mixture does Tal make? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #283586 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=283586\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=number of lbs of nut mixture used<BR>\n" );
document.write( "Now we know that the amount of pistachios that we have before the mixture takes place has to equal the amount of pistachios that we have after the mixture takes place.<BR>\n" );
document.write( "Amount of Pistachios before the mixture takes place:  5+0.70x<BR>\n" );
document.write( "Amount of pistachios after the mixture takes place: 0.80(5+x)<BR>\n" );
document.write( "So, our equation to solve is:<BR>\n" );
document.write( "5+0.70x=0.80(5+x) get rid of parens and simplify<BR>\n" );
document.write( "5+0.70x=4+0.80x  subtract 5 and also 0.80x from each side<BR>\n" );
document.write( "-0.10x=-1<BR>\n" );
document.write( "x=10 lbs------amount of nut mixture needed\r<BR>\n" );
document.write( "\n" );
document.write( "CK<BR>\n" );
document.write( "5+0.70*10=0.80*15<BR>\n" );
document.write( "5+7=12<BR>\n" );
document.write( "12=12\r<BR>\n" );
document.write( "\n" );
document.write( "Hope this helps---ptaylor </SPAN>\n" );
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