document.write( "Question 400540: In a fraction twice the numerator is 2 more than the numerator. If 3 is added to eachb the numerator and the denominator the new fraction formed is 2/3 find . F
\n" ); document.write( "ind the original fraction
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Algebra.Com's Answer #283550 by ankor@dixie-net.com(22740)\"\" \"About 
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\n" ); document.write( "In a fraction twice the numerator is 2 more than the denominator.
\n" ); document.write( "2n = d + 2
\n" ); document.write( "or
\n" ); document.write( "d = 2n - 2\r
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\n" ); document.write( "If 3 is added to each the numerator and the denominator the new fraction formed is 2/3.
\n" ); document.write( "\"%28n%2B3%29%2F%28d%2B3%29\" = \"2%2F3\"
\n" ); document.write( "Cross multiply
\n" ); document.write( "2(d+3) = 3(n+3)
\n" ); document.write( "2d + 6 = 3n + 9
\n" ); document.write( "2d = 3n + 9 - 6
\n" ); document.write( "2d = 3n + 3
\n" ); document.write( "replace d with (2n-2)
\n" ); document.write( "2(2n-2) = 3n + 3
\n" ); document.write( "4n - 4 = 3n + 3
\n" ); document.write( "4n - 3n = 3 + 4
\n" ); document.write( "n = 7 is the numerator
\n" ); document.write( "then
\n" ); document.write( "d = 2(7) - 2
\n" ); document.write( "d = 12
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\n" ); document.write( "\"7%2F12\" is the fraction
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\n" ); document.write( "Check solution
\n" ); document.write( "\"%287%2B3%29%2F%2812%2B3%29\" = \"10%2F15\" which is 2/3\r
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