document.write( "Question 400516: a boat traveled 45 miles downstream in 5 hours. the return trip took 9 hours upstream. what is the rate of the boat in still water in miles per hour? \n" ); document.write( "
Algebra.Com's Answer #283526 by Tatiana_Stebko(1539)\"\" \"About 
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Let x(mph)= the rate of the boat in still water
\n" ); document.write( "Let y mph = the rate of the river
\n" ); document.write( "When boat travels downstream the rate is (x+y)mph
\n" ); document.write( "From text:a boat traveled 45 miles downstream in 5 hours, so boat (downstream ) rate was \"45%2F5=9\" mph
\n" ); document.write( "We have the first equation of system
\n" ); document.write( "\"x%2By=9\"
\n" ); document.write( "When boat travels upstream the rate is (x-y) mph
\n" ); document.write( "From text:a boat traveled 45 miles downstream in 9 hours, so boat (upstream ) rate was \"45%2F9=5\" mph
\n" ); document.write( "the second equation is
\n" ); document.write( "\"x-y=5%29%29%29%0D%0ASolve+the+system%0D%0A%7B%7B%7Bx%2By=9\"
\n" ); document.write( "\"x-y=5%29%29%29%0D%0AAdd+the+first+equation+to+the+second%0D%0A%7B%7B%7B2x=14\"
\n" ); document.write( "\"x=14%2F2\"
\n" ); document.write( "\"x=7\" mph - the rate of the boat in still water
\n" ); document.write( "Answer 7 mph
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