document.write( "Question 400472: a rectangular garden is 9ft longer than it is wide. a second rectangular garden is planned so that it will be 6 ft wider and twice as long as the first garden. find the area of the first garden if the sum of the areas of both gardens will be 528 ft squared \n" ); document.write( "
Algebra.Com's Answer #283521 by lwsshak3(11628)\"\" \"About 
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a rectangular garden is 9ft longer than it is wide. a second rectangular garden is planned so that it will be 6 ft wider and twice as long as the first garden. find the area of the first garden if the sum of the areas of both gardens will be 528 ft squared\r
\n" ); document.write( "\n" ); document.write( "let x=width of first garden
\n" ); document.write( "then, x+9=length of first garden
\n" ); document.write( "then, x+6=width of second garden
\n" ); document.write( "then,2(x+9)=length of second garden
\n" ); document.write( "area = length*width\r
\n" ); document.write( "\n" ); document.write( "x(x+9)+(x+6)(2)(x+9)=528
\n" ); document.write( "x^2+9x+2(x^2+15x+54)=528
\n" ); document.write( "x^2+9x+2x^2+30x+108=528
\n" ); document.write( "3x^2+39x+108=528
\n" ); document.write( "3x^2+39x-420=0
\n" ); document.write( "x^2+13x-140=0
\n" ); document.write( "(x+20)(x-7)=0
\n" ); document.write( "x=-20(reject) or x=7
\n" ); document.write( "ans:area of first garden=x(x+9)=7*16=112sqft
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