document.write( "Question 43275: Find the area of the given triangle:
\n" ); document.write( "angle B = 20o
\n" ); document.write( "angle C = 115o
\n" ); document.write( "C = 16
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Algebra.Com's Answer #28351 by psbhowmick(878)\"\" \"About 
You can put this solution on YOUR website!
At first use sine rule.
\n" ); document.write( "\"b%2Fsin%28B%29+=+c%2Fsin%28C%29\"
\n" ); document.write( "or \"b%2Fsin%2820%5Eo%29+=+16%2Fsin%28115%5Eo%29\"
\n" ); document.write( "or \"b+=+16%2Asin%2820%5Eo%29%2Fsin%28115%5Eo%29\"
\n" ); document.write( "or \"b+=+16%2Asin%2820%5Eo%29%2Fsin%28180%5Eo+-+65%5Eo%29\"
\n" ); document.write( "or \"b+=+16%2Asin%2820%5Eo%29%2Fsin%2865%5Eo%29\"
\n" ); document.write( "or \"b+=+16%2A0.342%2F0.906\"
\n" ); document.write( "or \"b+=+6.038\"\r
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\n" ); document.write( "\n" ); document.write( "Now, in triangle ABC sum of the internal angles = \"180%5Eo\".
\n" ); document.write( "So, \"A+%2B+B+%2B+C+=+180%5Eo\"
\n" ); document.write( "or \"A+%2B+20%5Eo+%2B+115%5Eo+=+180%5Eo\"
\n" ); document.write( "or \"A+=+180%5Eo+-+20%5Eo+-+115%5Eo\"
\n" ); document.write( "or \"A+=+45%5Eo\"\r
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\n" ); document.write( "\n" ); document.write( "Now, area of triangle ABC is \"%281%2F2%29b%2Ac%2Asin%28A%29\" = \"%281%2F2%296.038%2A16%2Asin%2845%5Eo%29\" = 34.156 sq units.
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