document.write( "Question 400435: FIND THE WITDTH OF A RECTANGLE WHOSE WIDTH IS 1 MORE THAN TWICE ITS LENGTH AND WHOSE PERIMERTER IS 26
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Algebra.Com's Answer #283474 by algebrahouse.com(1659)\"\" \"About 
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FIND THE WITDTH OF A RECTANGLE WHOSE WIDTH IS 1 MORE THAN TWICE ITS LENGTH AND WHOSE PERIMERTER IS 26.\r
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\n" ); document.write( "\n" ); document.write( "x = length
\n" ); document.write( "2x + 1 = width {width is one more than twice the length}\r
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\n" ); document.write( "\n" ); document.write( "2(x) + 2(2x + 1) = 26 {two times width plus two times length equals perimeter}
\n" ); document.write( "2x + 4x + 2 = 26 {used distributive property}
\n" ); document.write( "6x + 2 = 26 {combined like terms}
\n" ); document.write( "6x = 24 {subtracted 2 from both sides}
\n" ); document.write( "x = 4 (length) {divided both sides by 4}
\n" ); document.write( "2x + 1 = 9 (width)
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