document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=400470>Question 400470</A>: <I><SPAN STYLE=\"word-break: break-all;\"> solve:\r<BR>\n" );
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document.write( "2x-3y=12<BR>\n" );
document.write( "4x-5y=-3 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #283466 by </B><A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><B>algebrahouse.com(1659)</B></A><img src=\"/images/stars/stars-12.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=algebrahouse.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=algebrahouse.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=283466\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2x - 3y = 12-----> -4x + 6y = -24 {multiplied top by -2}<BR>\n" );
document.write( "4x - 5y = -3------> 4x - 5y = -3 {bottom stays the same}\r<BR>\n" );
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document.write( "y = -27 {added the two new equations together} \r<BR>\n" );
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document.write( "2x - 3(-27) = 12 {substituted -27 in for y into top equation}<BR>\n" );
document.write( "2x + 81 = 12 {multiplied -3 by -27}<BR>\n" );
document.write( "2x = -69 {subtracted 81 from both sides}<BR>\n" );
document.write( "x = -69/2 {divided both sides by 2}<BR>\n" );
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