document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=43317>Question 43317</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I just don't even know what to say..................help!!!!!!!!!!!!!!!!!<BR>\n" );
document.write( "Given the following recursively defined sequence, find the fifth term.\r<BR>\n" );
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document.write( "a_1 = -4<BR>\n" );
document.write( "a_2 = -4<BR>\n" );
document.write( "a(_n+2)= a(_n+1)-4a_n\r<BR>\n" );
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document.write( "  a. 28    <BR>\n" );
document.write( "  b. 764    <BR>\n" );
document.write( "  c. -20    <BR>\n" );
document.write( "  d. -308    <BR>\n" );
document.write( "  e. None of the others    <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #28344 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=28344\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> This isn't as hard as you think...from<BR>\n" );
document.write( "a_(n+2)= a_(n+1) - 4a_n<BR>\n" );
document.write( "you merely plug in a_1 = -4 and a_2 = -4 to find a_3...<BR>\n" );
document.write( "a_3 = -4 - 4(-4) = 12 now continue<BR>\n" );
document.write( "a_4 = 12 - 4(-4) = 28<BR>\n" );
document.write( "a_5 = 28 - 4(12) = -20<BR>\n" );
document.write( "Choice C. </SPAN>\n" );
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