document.write( "Question 400380: Ok, I am working on graphing the quadratic 5x^2+10x+2=0 but I do not full understand how to do it \n" ); document.write( "
Algebra.Com's Answer #283437 by lwsshak3(11628)\"\" \"About 
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Ok, I am working on graphing the quadratic 5x^2+10x+2=0 but I do not full understand how to do it\r
\n" ); document.write( "\n" ); document.write( "You should first note that this is a parabola which opens upward because the coefficient of the x^2 is positive.
\n" ); document.write( "In order to graph it, you need to put it in this form: y=(x-h)^2+k, to find its vertex and x & y intercepts.For problems like this it would be very helpful to use a graphing calculator to see what the curve looks like.\r
\n" ); document.write( "\n" ); document.write( "y=5x^2+10x+2
\n" ); document.write( "completing the square
\n" ); document.write( "y=5(x^2+2x+1)-5+2
\n" ); document.write( "y=5(x+1)^2-3
\n" ); document.write( "This gives the (x,y) coordinates of the vertex (-1,-3)
\n" ); document.write( "To find the y-intercept, set x=0, then solve for y which by inspection you can see it is=2
\n" ); document.write( "To find the x-intercepts, set y-0, then solve for x
\n" ); document.write( "(x+1)^2=3/5
\n" ); document.write( "(x+1)=sqrt(3/5)
\n" ); document.write( "x=-1+-sqrt(3/5)
\n" ); document.write( "x=-1.77and x=-.22\r
\n" ); document.write( "\n" ); document.write( "You now have coordinates of the vertex, the y-intercept and the x intercepts to help you draw the curve.
\n" ); document.write( "It should look similar to the graph below:\r
\n" ); document.write( "\n" ); document.write( "\"+graph%28+300%2C+200%2C+-6%2C+5%2C+-10%2C+10%2C+5x%5E2%2B10x%2B2%29+\" \n" ); document.write( "
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