document.write( "Question 5480: a two digit number is 6 times its units digit. the sum of its digits is 3. Find the number.
\n" ); document.write( "thanks for the help! \n" ); document.write( "
Algebra.Com's Answer #2834 by Abbey(339)\"\" \"About 
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Let x be the digit in the 10's column
\n" ); document.write( "Let y be the digit in the one's column
\n" ); document.write( "So in order to find the value of the number we multiply the x by 10 and add it to the y (think about the number 23... it represents the value (2*10) + 3)
\n" ); document.write( "The number is written as 10x+y
\n" ); document.write( "The sum of the two digits is 3:
\n" ); document.write( "x+y=3
\n" ); document.write( "we can rewrite this by subtracting y from both sides as:
\n" ); document.write( "x=3-y
\n" ); document.write( "the number is 6 times the unit digit:
\n" ); document.write( "(6y=10x+y)
\n" ); document.write( "substitute the 3-y in for the x value and solve for y:
\n" ); document.write( "6y = 10(3-y)+y
\n" ); document.write( "6y = 30-10y+y
\n" ); document.write( "6y=30-9y
\n" ); document.write( "15y=30
\n" ); document.write( "y=2
\n" ); document.write( "if the sum of the digits is 3, then x=1
\n" ); document.write( "Our number is 12
\n" ); document.write( "check the answer:
\n" ); document.write( "2+1=3 (true)
\n" ); document.write( "12=6*2 (true) \r
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