document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=400295>Question 400295</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 2x^2-5=-55<BR>\n" );
document.write( "2x^2-50=0<BR>\n" );
document.write( "2(x^2-25)=0<BR>\n" );
document.write( "2(x-5)=0 2(x+5)=0\r<BR>\n" );
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document.write( "x=5 x=5 \r<BR>\n" );
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document.write( "I checked my work for both x's and it does not come out right for both I come up with 45=55. I am not wure what I am doing wrong here. What is the answer to x? Please show all work and how to check the answer.     </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #283379 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=283379\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> adding 5 ___ 2x^2 = -50\r<BR>\n" );
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document.write( "dividing by 2 ___ x^2 = -25\r<BR>\n" );
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document.write( "there are no REAL numbers that you can square and get a negative value\r<BR>\n" );
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document.write( "\"i\" is the notation used for the square root of -1\r<BR>\n" );
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document.write( "x^2 = 25(-1) = 25 i^2\r<BR>\n" );
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document.write( "taking square root ___ x = ±5i </SPAN>\n" );
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