document.write( "Question 400239: Verify:
\n" ); document.write( "cotθ-tanθ/sinθcosθ=csc²θ-sec²θ \n" ); document.write( "

Algebra.Com's Answer #283378 by lwsshak3(11628) $\"\"$ $\"About$

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Verify:
\n" ); document.write( "cotθ-tanθ/sinθcosθ=csc²θ-sec²θ\r
\n" ); document.write( "\n" ); document.write( "Start with left-hand side\r
\n" ); document.write( "\n" ); document.write( "cotθ-tanθ/sinθcosθ
\n" ); document.write( "=((cos/sin)-(sin/cos))/sincos
\n" ); document.write( "=((cos^2-sin^2)/sincos)/sincos
\n" ); document.write( "=(cos^2-sin^2)/(sincos)^2
\n" ); document.write( "=(cos^2/sin^2cos^2)-(sin^2/sin^2cos^2)
\n" ); document.write( "=(1/sin^2)-(1/cos^2) =csc^2-sec^2
\n" ); document.write( "left-hand side = right-hand side\r
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