document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=399923>Question 399923</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do i express this problem as a single logarithm please help\r<BR>\n" );
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document.write( "ln(x+1)+ln(4)-(1/2)ln(x) </SPAN>\n" );
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document.write( "ln(x+1)+ln(4)-(1/2)ln(x)\r<BR>\n" );
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document.write( "logarithmic rule: ln(m) + ln(n) = ln(mn)<BR>\n" );
document.write( "logarithmic rule: nln(m) = ln(m^n)<BR>\n" );
document.write( "logarithmic rule: ln(m) - ln(n) = ln(m/n)<BR>\n" );
document.write( "ln(x + 1) + ln(4) = ln(4(x + 1))<BR>\n" );
document.write( "(1/2)ln(x) = ln(x^(1/2))<BR>\n" );
document.write( "ln(4(x + 1)) - ln(x^(1/2)) = ln(4(x + 1)/x^(1/2))<BR>\n" );
document.write( "ln(4(x + 1)/x^(1/2)) = ln(4(x + 1)x^(1/2)/x)<BR>\n" );
document.write( "ln(4(x + 1)x^(1/2)/x) = ln((4x + 4)(x^(1/2))/x)<BR>\n" );
document.write( "ln((4x + 4)(x^(1/2))/x) = ln((4x^(3/2) + 4x^(1/2))/x)<BR>\n" );
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