document.write( "Question 5482: my questions is
\n" ); document.write( "a rectangle is 5 times as long as it is wide. the difference of its length and the width is 9 inches. find its perimeter.\r
\n" ); document.write( "\n" ); document.write( "thanks for the help
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Algebra.Com's Answer #2832 by Abbey(339)\"\" \"About 
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Let W = Width
\n" ); document.write( "Let L = Length\r
\n" ); document.write( "\n" ); document.write( "The length is = 5*width:
\n" ); document.write( "L=5W\r
\n" ); document.write( "\n" ); document.write( "The difference (subtraction) of it's length and width is 9 inches\r
\n" ); document.write( "\n" ); document.write( "L-W = 9\r
\n" ); document.write( "\n" ); document.write( "Substitute 5W in for the L in the subtraction equation:
\n" ); document.write( "\"5W-W=9\"
\n" ); document.write( "\"4W=9\"
\n" ); document.write( "divide both sides by 4
\n" ); document.write( "\"w=%289%2F4%29+inches\"
\n" ); document.write( "If it's length is 5 times the width, then:
\n" ); document.write( "\"5%289%2F4%29=45%2F4\"\r
\n" ); document.write( "\n" ); document.write( "The formula for a perimeter is
\n" ); document.write( "P=2L+2W
\n" ); document.write( "\"P=2%2845%2F4%29+%2B2%289%2F4%29\"
\n" ); document.write( "\"P=%2845%2F2%29%2B%289%2F2%29=%2854%2F2%29\" or 27 inches
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