document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=399915>Question 399915</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve: How much 2% alcohol must be mixed with 10% alcohol to get 2000ml of 8% alcohol?\r<BR>\n" );
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document.write( "Could you please show me step by step how you get the answer to this problem please? It's an applied problem. I just don't know how you solve this problem. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #283153 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=283153\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=amount of 2% alcohol needed<BR>\n" );
document.write( "Then 2000-x=amount of 10% alcohol needed<BR>\n" );
document.write( "Now we know that the amount of pure alcohol that we have before the mixture takes place has to equal the amount of pure alcohol that we have after the mixture takes place.\r<BR>\n" );
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document.write( "Amount of pure alcohol before the mixture takes place: 0.02x+0.10(2000-x)<BR>\n" );
document.write( "Amount of pure alcohol after the mixture takes place:  0.08*2000<BR>\n" );
document.write( "So, our equation to solve is:<BR>\n" );
document.write( "0.02x+0.10(2000-x)=0.08*2000 simplify and get rid of parens<BR>\n" );
document.write( "0.02x+200-0.10x=160 subtract 200 from each side and collect like terms<BR>\n" );
document.write( "-0.08x=-40 divide each by -0.08<BR>\n" );
document.write( "x=500ml-------------amount of 2% alcohol needed<BR>\n" );
document.write( "2000-500=1500ml---------------amount of 10% alcohol needed<BR>\n" );
document.write( "CK<BR>\n" );
document.write( "0.02*500+0.10*1500=0.08*2000<BR>\n" );
document.write( "10+150=160<BR>\n" );
document.write( "160=160\r<BR>\n" );
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document.write( "Hope this helps---ptaylor<BR>\n" );
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