document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=43288>Question 43288</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given magnitude and direction of vector, resolve it into its x and y components (-3, -120o) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #28315 by </B><A HREF=/tutors/aboutme.mpl?userid=fractalier><B>fractalier(6550)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=fractalier><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=fractalier><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=28315\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> x = r cos q<BR>\n" );
document.write( "y = r sin q<BR>\n" );
document.write( "Now we can look at (-3, -120°) as (3, 60°) so that<BR>\n" );
document.write( "x = 3 cos 60 = 3/2<BR>\n" );
document.write( "y = 3 sin 60 = 3*sqrt(3) / 2 </SPAN>\n" );
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