document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=399936>Question 399936</A>: <I><SPAN STYLE=\"word-break: break-all;\"> if three times a number is added to twice the same number the result is the same of thrice a number and 10 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #283148 by </B><A HREF=/tutors/aboutme.mpl?userid=ptaylor><B>ptaylor(2198)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ptaylor><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ptaylor><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=283148\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let x=the number<BR>\n" );
document.write( "3x=three time the number (same as thrice the number)<BR>\n" );
document.write( "2x=twice the same number<BR>\n" );
document.write( "When added together we get 2x+3x=5x<BR>\n" );
document.write( "Now we are told that:<BR>\n" );
document.write( "5x=3x+10  subtract 3x from both sides<BR>\n" );
document.write( "5x-3x=3x-3x+10<BR>\n" );
document.write( "2x=10<BR>\n" );
document.write( "x=5-------------------the number<BR>\n" );
document.write( "CK<BR>\n" );
document.write( "2*5+3*5=3.5+10<BR>\n" );
document.write( "10+15=15+10<BR>\n" );
document.write( "25=25\r<BR>\n" );
document.write( "\n" );
document.write( "Hope this helps---ptaylor<BR>\n" );
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