document.write( "Question 399547: Amanda can jog to work in 4/5 of an hour. When she rides her bike, it takes her 3/10 of an hour. If she rides 10 miles per hour faster than she jogs, how far away is her work?\r
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Algebra.Com's Answer #283082 by ankor@dixie-net.com(22740)\"\" \"About 
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Amanda can jog to work in 4/5 of an hour.
\n" ); document.write( " When she rides her bike, it takes her 3/10 of an hour.
\n" ); document.write( " If she rides 10 miles per hour faster than she jogs, how far away is her work?
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\n" ); document.write( "We can use decimals: 4/5 = .8 hrs; 3/10 = .3 hrs
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\n" ); document.write( "Find her speed jogging first
\n" ); document.write( "let s = her speed jogging
\n" ); document.write( "then
\n" ); document.write( "(s+10) = her speed biking
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\n" ); document.write( "Write a distance equation, dist = speed * time
\n" ); document.write( "jog dist = bike dist
\n" ); document.write( ".8s = .3(s+10)
\n" ); document.write( ".8s = .3s + 3
\n" ); document.write( ".8s - .3s = 3
\n" ); document.write( ".5s = 3
\n" ); document.write( "s = 3/.5
\n" ); document.write( "s = 6 mph is her jogging speed.
\n" ); document.write( "find the dist
\n" ); document.write( ".8 * 6 = 4.8 mi to work
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\n" ); document.write( "Check it by finding the dist on the bike (6+10 = 16 mph)
\n" ); document.write( ".3 * 16 = 4.8 mi also \n" ); document.write( "
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