document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=399819>Question 399819</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The lengths of the sides of a triangle are consecutive odd intergers. If the perimeter is 1 less than 4 times the shortest side, find the length of each side. <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #283077 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=283077\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The lengths of the sides of a triangle are consecutive odd intergers. If the perimeter is 1 less than 4 times the shortest side, find the length of each side. \r<BR>\n" );
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document.write( "let the length of the sides be x, x+2,x+4<BR>\n" );
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document.write( "x+x+2+x+4=4x-1<BR>\n" );
document.write( "3x+6=4x-1<BR>\n" );
document.write( "4x-3x=6+1<BR>\n" );
document.write( "x=7<BR>\n" );
document.write( "7, 9, 11\r<BR>\n" );
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document.write( "m.ananth@hotmail.ca </SPAN>\n" );
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