document.write( "Question 399469: In 4 years from now, Anna will be 2/3 of Mike's present age. In 11 years from now, Mike will be double Camilla's present age. 19 years ago, Anna was half as old as Camilla. How old are they now? \n" ); document.write( "
Algebra.Com's Answer #283075 by ankor@dixie-net.com(22740)\"\" \"About 
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let a = Anna's present age
\n" ); document.write( "let m = Mike's
\n" ); document.write( "let c = Camilla's
\n" ); document.write( ":
\n" ); document.write( "Write an equation for each statement, simplify into standard form:
\n" ); document.write( ":
\n" ); document.write( "\"In 4 years from now, Anna will be 2/3 of Mike's present age.\"
\n" ); document.write( " a + 4 = \"2%2F3\"m
\n" ); document.write( "Multiply by 3 to get rid of the fraction
\n" ); document.write( "3(a+4) = 2m
\n" ); document.write( "3a + 12 = 2m
\n" ); document.write( "3a - 2m = -12\r
\n" ); document.write( "\n" ); document.write( ":
\n" ); document.write( "\"In 11 years from now, Mike will be double Camilla's present age.\"
\n" ); document.write( "m + 11 = 2c
\n" ); document.write( "m - 2c = -11
\n" ); document.write( ":
\n" ); document.write( "\"19 years ago, Anna was half as old as Camilla.\"
\n" ); document.write( "a - 19 = \"1%2F2\"(c-19)
\n" ); document.write( "multiply by 2
\n" ); document.write( "2(a-19) = c - 19
\n" ); document.write( "2a - 38 = c - 19
\n" ); document.write( "2a - c = -19 + 38
\n" ); document.write( "2a - c = 19
\n" ); document.write( ":
\n" ); document.write( "See what we can do with these three equations:
\n" ); document.write( "3a - 2m + 0c = -12
\n" ); document.write( "0a + 1m - 2c = -11
\n" ); document.write( "2a + 0m - 1c = 19
\n" ); document.write( ":
\n" ); document.write( "Using the matrix feature in my Ti83, I got
\n" ); document.write( "a = 22 is Anna's age
\n" ); document.write( "m = 39 is Mike's age
\n" ); document.write( "c = 25 is Camilla's age\r
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